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1241301400113 = 3613674987167
BaseRepresentation
bin10010000100000011010…
…101000011101000110001
311101200000102120121211010
4102010003111003220301
5130314141124300423
62350125044541133
7155452414545165
oct22040325035061
94350012517733
101241301400113
11439484309315
121806a53b17a9
13900921755b8
144411789cca5
1522450a8c693
hex12103543a31

1241301400113 has 8 divisors (see below), whose sum is σ = 1657768484608. Its totient is φ = 826184291184.

The previous prime is 1241301400109. The next prime is 1241301400121. The reversal of 1241301400113 is 3110041031421.

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 1241301400113 - 22 = 1241301400109 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 1241301400113.

It is not an unprimeable number, because it can be changed into a prime (1241301400133) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 337491745 + ... + 337495422.

It is an arithmetic number, because the mean of its divisors is an integer number (207221060576).

Almost surely, 21241301400113 is an apocalyptic number.

It is an amenable number.

1241301400113 is a deficient number, since it is larger than the sum of its proper divisors (416467084495).

1241301400113 is an equidigital number, since it uses as much as digits as its factorization.

1241301400113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 674987783.

The product of its (nonzero) digits is 288, while the sum is 21.

Adding to 1241301400113 its reverse (3110041031421), we get a palindrome (4351342431534).

The spelling of 1241301400113 in words is "one trillion, two hundred forty-one billion, three hundred one million, four hundred thousand, one hundred thirteen".

Divisors: 1 3 613 1839 674987167 2024961501 413767133371 1241301400113