Base | Representation |
---|---|
bin | 1011010010100010001100… |
… | …0010110111101100010001 |
3 | 1121221200020100011220021111 |
4 | 2310220203002313230101 |
5 | 3111333403110043101 |
6 | 42222250132253321 |
7 | 2420545534225402 |
oct | 264504302675421 |
9 | 47850210156244 |
10 | 12413043440401 |
11 | 3a5638446200a |
12 | 1485893171241 |
13 | 6c07113cc3a6 |
14 | 30cb1a1b79a9 |
15 | 167d5999c251 |
hex | b4a230b7b11 |
12413043440401 has 8 divisors (see below), whose sum is σ = 12952994492160. Its totient is φ = 11873113514592.
The previous prime is 12413043440381. The next prime is 12413043440489. The reversal of 12413043440401 is 10404434031421.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-12413043440401 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (12413043440491) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 4074916 + ... + 6436693.
It is an arithmetic number, because the mean of its divisors is an integer number (1619124311520).
Almost surely, 212413043440401 is an apocalyptic number.
It is an amenable number.
12413043440401 is a deficient number, since it is larger than the sum of its proper divisors (539951051759).
12413043440401 is a wasteful number, since it uses less digits than its factorization.
12413043440401 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 10562975.
The product of its (nonzero) digits is 18432, while the sum is 31.
Adding to 12413043440401 its reverse (10404434031421), we get a palindrome (22817477471822).
The spelling of 12413043440401 in words is "twelve trillion, four hundred thirteen billion, forty-three million, four hundred forty thousand, four hundred one".
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