Base | Representation |
---|---|
bin | 10010000100000100000… |
… | …010001100000111101111 |
3 | 11101200001020211201012211 |
4 | 102010010002030013233 |
5 | 130314202141400333 |
6 | 2350130150311251 |
7 | 155452620242443 |
oct | 22040402140757 |
9 | 4350036751184 |
10 | 1241313231343 |
11 | 43948aa5a299 |
12 | 1806a9358527 |
13 | 90094758823 |
14 | 4411929c823 |
15 | 22451b27ecd |
hex | 1210408c1ef |
1241313231343 has 2 divisors, whose sum is σ = 1241313231344. Its totient is φ = 1241313231342.
The previous prime is 1241313231317. The next prime is 1241313231407. The reversal of 1241313231343 is 3431323131421.
It is a weak prime.
It is an emirp because it is prime and its reverse (3431323131421) is a distict prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1241313231343 is a prime.
It is a super-3 number, since 3×12413132313433 (a number of 37 digits) contains 333 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1241313238343) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 620656615671 + 620656615672.
It is an arithmetic number, because the mean of its divisors is an integer number (620656615672).
Almost surely, 21241313231343 is an apocalyptic number.
1241313231343 is a deficient number, since it is larger than the sum of its proper divisors (1).
1241313231343 is an equidigital number, since it uses as much as digits as its factorization.
1241313231343 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 15552, while the sum is 31.
Adding to 1241313231343 its reverse (3431323131421), we get a palindrome (4672636362764).
The spelling of 1241313231343 in words is "one trillion, two hundred forty-one billion, three hundred thirteen million, two hundred thirty-one thousand, three hundred forty-three".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.068 sec. • engine limits •