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12414124313002 = 26207062156501
BaseRepresentation
bin1011010010100110001101…
…1110000100100110101010
31121221210000200000220202001
42310221203132010212222
53111343111311004002
642222545303201214
72420614400415436
oct264514336044652
947853020026661
1012414124313002
113a568895a2655
121485b3514620a
136c0854313b89
1430cbbd9779c6
15167dbe805a87
hexb4a637849aa

12414124313002 has 4 divisors (see below), whose sum is σ = 18621186469506. Its totient is φ = 6207062156500.

The previous prime is 12414124312963. The next prime is 12414124313039. The reversal of 12414124313002 is 20031342141421.

It is a happy number.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in only one way, i.e., 8436927720321 + 3977196592681 = 2904639^2 + 1994291^2 .

It is a super-2 number, since 2×124141243130022 (a number of 27 digits) contains 22 as substring.

It is an unprimeable number.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 3103531078249 + ... + 3103531078252.

Almost surely, 212414124313002 is an apocalyptic number.

12414124313002 is a deficient number, since it is larger than the sum of its proper divisors (6207062156504).

12414124313002 is an equidigital number, since it uses as much as digits as its factorization.

12414124313002 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 6207062156503.

The product of its (nonzero) digits is 4608, while the sum is 28.

Adding to 12414124313002 its reverse (20031342141421), we get a palindrome (32445466454423).

The spelling of 12414124313002 in words is "twelve trillion, four hundred fourteen billion, one hundred twenty-four million, three hundred thirteen thousand, two".

Divisors: 1 2 6207062156501 12414124313002