12414135433 has 8 divisors (see below), whose sum is σ = 14211273600. Its totient is φ = 10622919840.

The previous prime is 12414135413. The next prime is 12414135439. The reversal of 12414135433 is 33453141421.

12414135433 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 12414135433 - 2⁹ = 12414134921 is a prime.

It is a super-2 number, since 2×12414135433² (a number of 21 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 12414135395 and 12414135404.

It is not an unprimeable number, because it can be changed into a prime (12414135439) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 1476148 + ... + 1484533.

It is an arithmetic number, because the mean of its divisors is an integer number (1776409200).

Almost surely, 2^12414135433 is an apocalyptic number.

It is an amenable number.

12414135433 is a deficient number, since it is larger than the sum of its proper divisors (1797138167).

12414135433 is an equidigital number, since it uses as much as digits as its factorization.

12414135433 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 2961287.

The product of its digits is 17280, while the sum is 31.

Adding to 12414135433 its reverse (33453141421), we get a palindrome (45867276854).

The spelling of 12414135433 in words is "twelve billion, four hundred fourteen million, one hundred thirty-five thousand, four hundred thirty-three".