Search a number
-
+
1241532015242 = 2620766007621
BaseRepresentation
bin10010000100010001000…
…100110010001010001010
311101200121111112002022012
4102010101010302022022
5130320124143441432
62350204003455522
7155461215002411
oct22042104621212
94350544462265
101241532015242
11439592501932
1218074a6875a2
13900cab8b85c
144413a370478
1522465e42cb2
hex1211113228a

1241532015242 has 4 divisors (see below), whose sum is σ = 1862298022866. Its totient is φ = 620766007620.

The previous prime is 1241532015223. The next prime is 1241532015253. The reversal of 1241532015242 is 2425102351421.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in only one way, i.e., 829882738441 + 411649276801 = 910979^2 + 641599^2 .

It is a junction number, because it is equal to n+sod(n) for n = 1241532015199 and 1241532015208.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 310383003809 + ... + 310383003812.

Almost surely, 21241532015242 is an apocalyptic number.

1241532015242 is a deficient number, since it is larger than the sum of its proper divisors (620766007624).

1241532015242 is an equidigital number, since it uses as much as digits as its factorization.

1241532015242 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 620766007623.

The product of its (nonzero) digits is 19200, while the sum is 32.

Adding to 1241532015242 its reverse (2425102351421), we get a palindrome (3666634366663).

The spelling of 1241532015242 in words is "one trillion, two hundred forty-one billion, five hundred thirty-two million, fifteen thousand, two hundred forty-two".

Divisors: 1 2 620766007621 1241532015242