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1241532213041 is a prime number
BaseRepresentation
bin10010000100010001000…
…101100010011100110001
311101200121111220010122002
4102010101011202130301
5130320124221304131
62350204012023345
7155461216455161
oct22042105423461
94350544803562
101241532213041
114395926274aa
1218074a761b55
13900cac2a8b3
144413a3c25a1
1522465e816cb
hex12111162731

1241532213041 has 2 divisors, whose sum is σ = 1241532213042. Its totient is φ = 1241532213040.

The previous prime is 1241532213017. The next prime is 1241532213059. The reversal of 1241532213041 is 1403122351421.

It is a happy number.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 676210182400 + 565322030641 = 822320^2 + 751879^2 .

It is a cyclic number.

It is not a de Polignac number, because 1241532213041 - 210 = 1241532212017 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 1241532212995 and 1241532213013.

It is not a weakly prime, because it can be changed into another prime (1241532273041) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 620766106520 + 620766106521.

It is an arithmetic number, because the mean of its divisors is an integer number (620766106521).

Almost surely, 21241532213041 is an apocalyptic number.

It is an amenable number.

1241532213041 is a deficient number, since it is larger than the sum of its proper divisors (1).

1241532213041 is an equidigital number, since it uses as much as digits as its factorization.

1241532213041 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 5760, while the sum is 29.

Adding to 1241532213041 its reverse (1403122351421), we get a palindrome (2644654564462).

The spelling of 1241532213041 in words is "one trillion, two hundred forty-one billion, five hundred thirty-two million, two hundred thirteen thousand, forty-one".