Base | Representation |
---|---|
bin | 10111001000010010… |
… | …01100101100100111 |
3 | 1012001101210221211121 |
4 | 23210021030230213 |
5 | 200412343114033 |
6 | 5412103114411 |
7 | 616501305004 |
oct | 134411145447 |
9 | 35041727747 |
10 | 12417551143 |
11 | 52a2424a68 |
12 | 24a6742a07 |
13 | 122b80c9ca |
14 | 85b2708ab |
15 | 4ca24e62d |
hex | 2e424cb27 |
12417551143 has 2 divisors, whose sum is σ = 12417551144. Its totient is φ = 12417551142.
The previous prime is 12417551131. The next prime is 12417551149. The reversal of 12417551143 is 34115571421.
It is a strong prime.
It is an emirp because it is prime and its reverse (34115571421) is a distict prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-12417551143 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 12417551099 and 12417551108.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (12417551149) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6208775571 + 6208775572.
It is an arithmetic number, because the mean of its divisors is an integer number (6208775572).
Almost surely, 212417551143 is an apocalyptic number.
12417551143 is a deficient number, since it is larger than the sum of its proper divisors (1).
12417551143 is an equidigital number, since it uses as much as digits as its factorization.
12417551143 is an evil number, because the sum of its binary digits is even.
The product of its digits is 16800, while the sum is 34.
The spelling of 12417551143 in words is "twelve billion, four hundred seventeen million, five hundred fifty-one thousand, one hundred forty-three".
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