Base | Representation |
---|---|
bin | 10010000100101101110… |
… | …000110100011110110101 |
3 | 11101201212001011221212121 |
4 | 102010231300310132311 |
5 | 130322120402234031 |
6 | 2350323435515541 |
7 | 155506151016535 |
oct | 22045560643665 |
9 | 4351761157777 |
10 | 1242013321141 |
11 | 43980a1600aa |
12 | 1808638b8bb1 |
13 | 901767c9a48 |
14 | 4418425b4c5 |
15 | 22493317011 |
hex | 1212dc347b5 |
1242013321141 has 2 divisors, whose sum is σ = 1242013321142. Its totient is φ = 1242013321140.
The previous prime is 1242013321127. The next prime is 1242013321147. The reversal of 1242013321141 is 1411233102421.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 1232433022500 + 9580298641 = 1110150^2 + 97879^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1242013321141 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1242013321147) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 621006660570 + 621006660571.
It is an arithmetic number, because the mean of its divisors is an integer number (621006660571).
Almost surely, 21242013321141 is an apocalyptic number.
It is an amenable number.
1242013321141 is a deficient number, since it is larger than the sum of its proper divisors (1).
1242013321141 is an equidigital number, since it uses as much as digits as its factorization.
1242013321141 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1152, while the sum is 25.
Adding to 1242013321141 its reverse (1411233102421), we get a palindrome (2653246423562).
The spelling of 1242013321141 in words is "one trillion, two hundred forty-two billion, thirteen million, three hundred twenty-one thousand, one hundred forty-one".
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