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12421300412103 = 3111480912541701
BaseRepresentation
bin1011010011000000111100…
…1100101101111011000111
31121222110112210010112002020
42310300033030231323013
53112002310401141403
642230133332014223
72421260255305242
oct264601714557307
947873483115066
1012421300412103
113a59931295070
1214873b8461373
136c1428c5626b
1430d2a0a54259
1516818e807453
hexb4c0f32dec7

12421300412103 has 16 divisors (see below), whose sum is σ = 18067475164032. Its totient is φ = 7528007060000.

The previous prime is 12421300412051. The next prime is 12421300412119. The reversal of 12421300412103 is 30121400312421.

It is a cyclic number.

It is not a de Polignac number, because 12421300412103 - 217 = 12421300281031 is a prime.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (12421300412303) by changing a digit.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 3616153 + ... + 6157853.

It is an arithmetic number, because the mean of its divisors is an integer number (1129217197752).

Almost surely, 212421300412103 is an apocalyptic number.

12421300412103 is a deficient number, since it is larger than the sum of its proper divisors (5646174751929).

12421300412103 is a wasteful number, since it uses less digits than its factorization.

12421300412103 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 2689806.

The product of its (nonzero) digits is 1152, while the sum is 24.

Adding to 12421300412103 its reverse (30121400312421), we get a palindrome (42542700724524).

The spelling of 12421300412103 in words is "twelve trillion, four hundred twenty-one billion, three hundred million, four hundred twelve thousand, one hundred three".

Divisors: 1 3 11 33 148091 444273 1629001 2541701 4887003 7625103 27958711 83876133 376403042791 1129209128373 4140433470701 12421300412103