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124213235021143 is a prime number
BaseRepresentation
bin11100001111100010100101…
…101111111111010101010111
3121021210200001220210011020021
4130033202211233333111113
5112240102201131134033
61120102434501250011
735110052521026622
oct3417424557772527
9537720056704207
10124213235021143
113663a59aa34284
1211b21435103907
135440347512b18
142295d4a116db9
15e5611095cb2d
hex70f8a5bff557

124213235021143 has 2 divisors, whose sum is σ = 124213235021144. Its totient is φ = 124213235021142.

The previous prime is 124213235021131. The next prime is 124213235021203. The reversal of 124213235021143 is 341120532312421.

It is a weak prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-124213235021143 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 124213235021099 and 124213235021108.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (124213235022143) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 62106617510571 + 62106617510572.

It is an arithmetic number, because the mean of its divisors is an integer number (62106617510572).

Almost surely, 2124213235021143 is an apocalyptic number.

124213235021143 is a deficient number, since it is larger than the sum of its proper divisors (1).

124213235021143 is an equidigital number, since it uses as much as digits as its factorization.

124213235021143 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 34560, while the sum is 34.

Adding to 124213235021143 its reverse (341120532312421), we get a palindrome (465333767333564).

The spelling of 124213235021143 in words is "one hundred twenty-four trillion, two hundred thirteen billion, two hundred thirty-five million, twenty-one thousand, one hundred forty-three".