1242140411203 has 2 divisors, whose sum is σ = 1242140411204. Its totient is φ = 1242140411202.

The previous prime is 1242140411111. The next prime is 1242140411219. The reversal of 1242140411203 is 3021140412421.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-1242140411203 is a prime.

It is a super-3 number, since 3×1242140411203³ (a number of 37 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is not a weakly prime, because it can be changed into another prime (1242140411503) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 621070205601 + 621070205602.

It is an arithmetic number, because the mean of its divisors is an integer number (621070205602).

Almost surely, 2^{1242140411203} is an apocalyptic number.

1242140411203 is a deficient number, since it is larger than the sum of its proper divisors (1).

1242140411203 is an equidigital number, since it uses as much as digits as its factorization.

1242140411203 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1536, while the sum is 25.

Adding to 1242140411203 its reverse (3021140412421), we get a palindrome (4263280823624).

The spelling of 1242140411203 in words is "one trillion, two hundred forty-two billion, one hundred forty million, four hundred eleven thousand, two hundred three".