Base | Representation |
---|---|
bin | 10111001000110100… |
… | …10111011001101001 |
3 | 1012001201021121002000 |
4 | 23210122113121221 |
5 | 200420021121213 |
6 | 5412343401213 |
7 | 616554460251 |
oct | 134432273151 |
9 | 35051247060 |
10 | 12422051433 |
11 | 52a4a19110 |
12 | 24a8153209 |
13 | 122c7271bc |
14 | 85bac2961 |
15 | 4ca83cc73 |
hex | 2e4697669 |
12422051433 has 32 divisors (see below), whose sum is σ = 20087930880. Its totient is φ = 7524058320.
The previous prime is 12422051387. The next prime is 12422051443. The reversal of 12422051433 is 33415022421.
12422051433 is a `hidden beast` number, since 1 + 2 + 4 + 220 + 5 + 1 + 433 = 666.
It is not a de Polignac number, because 12422051433 - 216 = 12421985897 is a prime.
It is a Harshad number since it is a multiple of its sum of digits (27).
It is a junction number, because it is equal to n+sod(n) for n = 12422051397 and 12422051406.
It is not an unprimeable number, because it can be changed into a prime (12422051443) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 529960 + ... + 552902.
It is an arithmetic number, because the mean of its divisors is an integer number (627747840).
Almost surely, 212422051433 is an apocalyptic number.
It is an amenable number.
12422051433 is a deficient number, since it is larger than the sum of its proper divisors (7665879447).
12422051433 is a wasteful number, since it uses less digits than its factorization.
12422051433 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 24786 (or 24780 counting only the distinct ones).
The product of its (nonzero) digits is 5760, while the sum is 27.
Adding to 12422051433 its reverse (33415022421), we get a palindrome (45837073854).
The spelling of 12422051433 in words is "twelve billion, four hundred twenty-two million, fifty-one thousand, four hundred thirty-three".
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