Base | Representation |
---|---|
bin | 11100001111110101000010… |
… | …110100101011000111001011 |
3 | 121021212120012212102112210011 |
4 | 130033311002310223013023 |
5 | 112240413241314004011 |
6 | 1120115513024132351 |
7 | 35111353536542011 |
oct | 3417650264530713 |
9 | 537776185375704 |
10 | 124233050141131 |
11 | 36647a390681a8 |
12 | 11b252451670b7 |
13 | 54421847c85a9 |
14 | 2296ca9a348b1 |
15 | e568c0359621 |
hex | 70fd42d2b1cb |
124233050141131 has 2 divisors, whose sum is σ = 124233050141132. Its totient is φ = 124233050141130.
The previous prime is 124233050141059. The next prime is 124233050141171. The reversal of 124233050141131 is 131141050332421.
It is a happy number.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 124233050141131 - 217 = 124233050010059 is a prime.
It is a super-2 number, since 2×1242330501411312 (a number of 29 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 124233050141093 and 124233050141102.
It is not a weakly prime, because it can be changed into another prime (124233050141171) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 62116525070565 + 62116525070566.
It is an arithmetic number, because the mean of its divisors is an integer number (62116525070566).
Almost surely, 2124233050141131 is an apocalyptic number.
124233050141131 is a deficient number, since it is larger than the sum of its proper divisors (1).
124233050141131 is an equidigital number, since it uses as much as digits as its factorization.
124233050141131 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 8640, while the sum is 31.
The spelling of 124233050141131 in words is "one hundred twenty-four trillion, two hundred thirty-three billion, fifty million, one hundred forty-one thousand, one hundred thirty-one".
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