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1242471300013 = 1796941180447
BaseRepresentation
bin10010000101001001000…
…011110111101110101101
311101210000221221200210001
4102011021003313232231
5130324040123100023
62350441115544301
7155523411540106
oct22051103675655
94353027850701
101242471300013
11439a24726439
1218097115b091
139021a65b368
14441c8dd53ad
15224bd62e6ad
hex121490f7bad

1242471300013 has 4 divisors (see below), whose sum is σ = 1249412480640. Its totient is φ = 1235530119388.

The previous prime is 1242471299983. The next prime is 1242471300079. The reversal of 1242471300013 is 3100031742421.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 1242471300013 - 25 = 1242471299981 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1242471300113) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3470590045 + ... + 3470590402.

It is an arithmetic number, because the mean of its divisors is an integer number (312353120160).

Almost surely, 21242471300013 is an apocalyptic number.

It is an amenable number.

1242471300013 is a deficient number, since it is larger than the sum of its proper divisors (6941180627).

1242471300013 is an equidigital number, since it uses as much as digits as its factorization.

1242471300013 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 6941180626.

The product of its (nonzero) digits is 4032, while the sum is 28.

The spelling of 1242471300013 in words is "one trillion, two hundred forty-two billion, four hundred seventy-one million, three hundred thousand, thirteen".

Divisors: 1 179 6941180447 1242471300013