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12426231302549 is a prime number
BaseRepresentation
bin1011010011010011010100…
…0110100100100110010101
31121222221021102110201011022
42310310311012210212111
53112042410203140144
642232310514050525
72421523411215161
oct264646506444625
947887242421138
1012426231302549
113a60a3168a039
121488353879a45
136c1a3369870c
1430d60b885ca1
1516837c65bcee
hexb4d351a4995

12426231302549 has 2 divisors, whose sum is σ = 12426231302550. Its totient is φ = 12426231302548.

The previous prime is 12426231302543. The next prime is 12426231302587. The reversal of 12426231302549 is 94520313262421.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 8609705692900 + 3816525609649 = 2934230^2 + 1953593^2 .

It is an emirp because it is prime and its reverse (94520313262421) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 12426231302549 - 28 = 12426231302293 is a prime.

It is a super-2 number, since 2×124262313025492 (a number of 27 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (12426231302543) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6213115651274 + 6213115651275.

It is an arithmetic number, because the mean of its divisors is an integer number (6213115651275).

Almost surely, 212426231302549 is an apocalyptic number.

It is an amenable number.

12426231302549 is a deficient number, since it is larger than the sum of its proper divisors (1).

12426231302549 is an equidigital number, since it uses as much as digits as its factorization.

12426231302549 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 622080, while the sum is 44.

The spelling of 12426231302549 in words is "twelve trillion, four hundred twenty-six billion, two hundred thirty-one million, three hundred two thousand, five hundred forty-nine".