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12432324433 is a prime number
BaseRepresentation
bin10111001010000011…
…00011011101010001
31012002102121111222111
423211001203131101
5200430133340213
65413351505321
7620041004554
oct134501433521
935072544874
1012432324433
1152aa7a53a1
1224ab688241
1312318b30b9
1485d1d869b
154cb6bba3d
hex2e5063751

12432324433 has 2 divisors, whose sum is σ = 12432324434. Its totient is φ = 12432324432.

The previous prime is 12432324361. The next prime is 12432324439. The reversal of 12432324433 is 33442323421.

It is a happy number.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 7216162704 + 5216161729 = 84948^2 + 72223^2 .

It is a cyclic number.

It is not a de Polignac number, because 12432324433 - 233 = 3842389841 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 12432324395 and 12432324404.

It is not a weakly prime, because it can be changed into another prime (12432324439) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6216162216 + 6216162217.

It is an arithmetic number, because the mean of its divisors is an integer number (6216162217).

Almost surely, 212432324433 is an apocalyptic number.

It is an amenable number.

12432324433 is a deficient number, since it is larger than the sum of its proper divisors (1).

12432324433 is an equidigital number, since it uses as much as digits as its factorization.

12432324433 is an evil number, because the sum of its binary digits is even.

The product of its digits is 41472, while the sum is 31.

Adding to 12432324433 its reverse (33442323421), we get a palindrome (45874647854).

The spelling of 12432324433 in words is "twelve billion, four hundred thirty-two million, three hundred twenty-four thousand, four hundred thirty-three".