Base | Representation |
---|---|
bin | 111001111001010111… |
… | …0011011100100100101 |
3 | 102212220212100120212212 |
4 | 1303302232123210211 |
5 | 4014112310421432 |
6 | 133041140053205 |
7 | 11661021653663 |
oct | 1636256334445 |
9 | 385825316785 |
10 | 124331342117 |
11 | 4880188a604 |
12 | 2011a394205 |
13 | b95565b6b8 |
14 | 60366abc33 |
15 | 337a37b2b2 |
hex | 1cf2b9b925 |
124331342117 has 2 divisors, whose sum is σ = 124331342118. Its totient is φ = 124331342116.
The previous prime is 124331342089. The next prime is 124331342141. The reversal of 124331342117 is 711243133421.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 92756184481 + 31575157636 = 304559^2 + 177694^2 .
It is a cyclic number.
It is not a de Polignac number, because 124331342117 - 226 = 124264233253 is a prime.
It is a super-2 number, since 2×1243313421172 (a number of 23 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (124331344117) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 62165671058 + 62165671059.
It is an arithmetic number, because the mean of its divisors is an integer number (62165671059).
Almost surely, 2124331342117 is an apocalyptic number.
It is an amenable number.
124331342117 is a deficient number, since it is larger than the sum of its proper divisors (1).
124331342117 is an equidigital number, since it uses as much as digits as its factorization.
124331342117 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 12096, while the sum is 32.
Adding to 124331342117 its reverse (711243133421), we get a palindrome (835574475538).
The spelling of 124331342117 in words is "one hundred twenty-four billion, three hundred thirty-one million, three hundred forty-two thousand, one hundred seventeen".
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