12433135101 has 4 divisors (see below), whose sum is σ = 16577513472. Its totient is φ = 8288756732.

The previous prime is 12433135073. The next prime is 12433135151. The reversal of 12433135101 is 10153133421.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 12433135101 - 2⁵ = 12433135069 is a prime.

It is a Curzon number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (12433135151) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2072189181 + ... + 2072189186.

It is an arithmetic number, because the mean of its divisors is an integer number (4144378368).

Almost surely, 2^12433135101 is an apocalyptic number.

It is an amenable number.

12433135101 is a deficient number, since it is larger than the sum of its proper divisors (4144378371).

12433135101 is an equidigital number, since it uses as much as digits as its factorization.

12433135101 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 4144378370.

The product of its (nonzero) digits is 1080, while the sum is 24.

Adding to 12433135101 its reverse (10153133421), we get a palindrome (22586268522).

The spelling of 12433135101 in words is "twelve billion, four hundred thirty-three million, one hundred thirty-five thousand, one hundred one".