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124331440213481 is a prime number
BaseRepresentation
bin11100010001010000101011…
…010101000000110111101001
3121022012222011211201002110212
4130101100223111000313221
5112244021242143312411
61120233024120550505
735121435664421624
oct3421205325006751
9538188154632425
10124331440213481
1136685738760886
1211b40323922435
13544b534907607
14229b960d38dbb
15e5922d08368b
hex71142b540de9

124331440213481 has 2 divisors, whose sum is σ = 124331440213482. Its totient is φ = 124331440213480.

The previous prime is 124331440213433. The next prime is 124331440213507. The reversal of 124331440213481 is 184312044133421.

It is a happy number.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 124007912461456 + 323527752025 = 11135884^2 + 568795^2 .

It is a cyclic number.

It is not a de Polignac number, because 124331440213481 - 218 = 124331439951337 is a prime.

It is a super-2 number, since 2×1243314402134812 (a number of 29 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (124331440213081) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 62165720106740 + 62165720106741.

It is an arithmetic number, because the mean of its divisors is an integer number (62165720106741).

Almost surely, 2124331440213481 is an apocalyptic number.

It is an amenable number.

124331440213481 is a deficient number, since it is larger than the sum of its proper divisors (1).

124331440213481 is an equidigital number, since it uses as much as digits as its factorization.

124331440213481 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 221184, while the sum is 41.

The spelling of 124331440213481 in words is "one hundred twenty-four trillion, three hundred thirty-one billion, four hundred forty million, two hundred thirteen thousand, four hundred eighty-one".