Search a number
-
+
1243324002143 = 6938317919721
BaseRepresentation
bin10010000101111011111…
…000101010111101011111
311101212020101110110012102
4102011323320222331133
5130332311421032033
62351101500155315
7155553504434126
oct22057370527537
94355211413172
101243324002143
1143a321a93143
12180b6a838b3b
1390325204532
144426a35cabd
152251d416de8
hex1217be2af5f

1243324002143 has 4 divisors (see below), whose sum is σ = 1243341991248. Its totient is φ = 1243306013040.

The previous prime is 1243324002097. The next prime is 1243324002251. The reversal of 1243324002143 is 3412004233421.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 1243324002143 - 216 = 1243323936607 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1243324002043) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 8890478 + ... + 9029243.

It is an arithmetic number, because the mean of its divisors is an integer number (310835497812).

Almost surely, 21243324002143 is an apocalyptic number.

1243324002143 is a deficient number, since it is larger than the sum of its proper divisors (17989105).

1243324002143 is an equidigital number, since it uses as much as digits as its factorization.

1243324002143 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 17989104.

The product of its (nonzero) digits is 13824, while the sum is 29.

Adding to 1243324002143 its reverse (3412004233421), we get a palindrome (4655328235564).

The spelling of 1243324002143 in words is "one trillion, two hundred forty-three billion, three hundred twenty-four million, two thousand, one hundred forty-three".

Divisors: 1 69383 17919721 1243324002143