Base | Representation |
---|---|
bin | 10010000101111011111… |
… | …000101010111101011111 |
3 | 11101212020101110110012102 |
4 | 102011323320222331133 |
5 | 130332311421032033 |
6 | 2351101500155315 |
7 | 155553504434126 |
oct | 22057370527537 |
9 | 4355211413172 |
10 | 1243324002143 |
11 | 43a321a93143 |
12 | 180b6a838b3b |
13 | 90325204532 |
14 | 4426a35cabd |
15 | 2251d416de8 |
hex | 1217be2af5f |
1243324002143 has 4 divisors (see below), whose sum is σ = 1243341991248. Its totient is φ = 1243306013040.
The previous prime is 1243324002097. The next prime is 1243324002251. The reversal of 1243324002143 is 3412004233421.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 1243324002143 - 216 = 1243323936607 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (1243324002043) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 8890478 + ... + 9029243.
It is an arithmetic number, because the mean of its divisors is an integer number (310835497812).
Almost surely, 21243324002143 is an apocalyptic number.
1243324002143 is a deficient number, since it is larger than the sum of its proper divisors (17989105).
1243324002143 is an equidigital number, since it uses as much as digits as its factorization.
1243324002143 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 17989104.
The product of its (nonzero) digits is 13824, while the sum is 29.
Adding to 1243324002143 its reverse (3412004233421), we get a palindrome (4655328235564).
The spelling of 1243324002143 in words is "one trillion, two hundred forty-three billion, three hundred twenty-four million, two thousand, one hundred forty-three".
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