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1243340132 = 22310835033
BaseRepresentation
bin100101000011011…
…1101110101100100
310012122120020000112
41022012331311210
510021243341012
6323213032152
742545134226
oct11206756544
93178506015
101243340132
11588918931
122a8485658
1316a78a428
14bb1b2416
157424c122
hex4a1bdd64

1243340132 has 6 divisors (see below), whose sum is σ = 2175845238. Its totient is φ = 621670064.

The previous prime is 1243340117. The next prime is 1243340149. The reversal of 1243340132 is 2310433421.

It can be written as a sum of positive squares in only one way, i.e., 1242844516 + 495616 = 35254^2 + 704^2 .

It is a junction number, because it is equal to n+sod(n) for n = 1243340098 and 1243340107.

It is an unprimeable number.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 155417513 + ... + 155417520.

It is an arithmetic number, because the mean of its divisors is an integer number (362640873).

Almost surely, 21243340132 is an apocalyptic number.

It is an amenable number.

1243340132 is a deficient number, since it is larger than the sum of its proper divisors (932505106).

1243340132 is a wasteful number, since it uses less digits than its factorization.

1243340132 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 310835037 (or 310835035 counting only the distinct ones).

The product of its (nonzero) digits is 1728, while the sum is 23.

The square root of 1243340132 is about 35261.0285159126. The cubic root of 1243340132 is about 1075.3008372383.

Adding to 1243340132 its reverse (2310433421), we get a palindrome (3553773553).

The spelling of 1243340132 in words is "one billion, two hundred forty-three million, three hundred forty thousand, one hundred thirty-two".

Divisors: 1 2 4 310835033 621670066 1243340132