Base | Representation |
---|---|
bin | 10111001010010000… |
… | …11100010101000001 |
3 | 1012002120000021002021 |
4 | 23211020130111001 |
5 | 200431114131431 |
6 | 5413454321441 |
7 | 620062235401 |
oct | 134510342501 |
9 | 35076007067 |
10 | 12434130241 |
11 | 53008190a5 |
12 | 24b01b9281 |
13 | 1232096020 |
14 | 85d548801 |
15 | 4cb926b11 |
hex | 2e521c541 |
12434130241 has 4 divisors (see below), whose sum is σ = 13390601812. Its totient is φ = 11477658672.
The previous prime is 12434130239. The next prime is 12434130251. The reversal of 12434130241 is 14203143421.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in 2 ways, for example, as 1973136400 + 10460993841 = 44420^2 + 102279^2 .
It is a cyclic number.
It is not a de Polignac number, because 12434130241 - 21 = 12434130239 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (12434130251) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 478235766 + ... + 478235791.
It is an arithmetic number, because the mean of its divisors is an integer number (3347650453).
Almost surely, 212434130241 is an apocalyptic number.
It is an amenable number.
12434130241 is a deficient number, since it is larger than the sum of its proper divisors (956471571).
12434130241 is an equidigital number, since it uses as much as digits as its factorization.
12434130241 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 956471570.
The product of its (nonzero) digits is 2304, while the sum is 25.
Adding to 12434130241 its reverse (14203143421), we get a palindrome (26637273662).
The spelling of 12434130241 in words is "twelve billion, four hundred thirty-four million, one hundred thirty thousand, two hundred forty-one".
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