Base | Representation |
---|---|
bin | 11100010001011011100100… |
… | …001000100010010010100010 |
3 | 121022021002100120100102002111 |
4 | 130101123210020202102202 |
5 | 112244214212422141200 |
6 | 1120242240131505534 |
7 | 35122331456535226 |
oct | 3421334410422242 |
9 | 538232316312074 |
10 | 124343130662050 |
11 | 3668a697704923 |
12 | 11b42646a582aa |
13 | 544c6788a89c1 |
14 | 229c34d7b8786 |
15 | e596b455a0ba |
hex | 7116e42224a2 |
124343130662050 has 96 divisors (see below), whose sum is σ = 247176893952000. Its totient is φ = 46374657960960.
The previous prime is 124343130662041. The next prime is 124343130662071. The reversal of 124343130662050 is 50266031343421.
It is a super-2 number, since 2×1243431306620502 (a number of 29 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 124343130661994 and 124343130662012.
It is an unprimeable number.
It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 46705119 + ... + 49295581.
It is an arithmetic number, because the mean of its divisors is an integer number (2574759312000).
Almost surely, 2124343130662050 is an apocalyptic number.
124343130662050 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
124343130662050 is a deficient number, since it is larger than the sum of its proper divisors (122833763289950).
124343130662050 is a wasteful number, since it uses less digits than its factorization.
124343130662050 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 2591020 (or 2591015 counting only the distinct ones).
The product of its (nonzero) digits is 311040, while the sum is 40.
The spelling of 124343130662050 in words is "one hundred twenty-four trillion, three hundred forty-three billion, one hundred thirty million, six hundred sixty-two thousand, fifty".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.092 sec. • engine limits •