Base | Representation |
---|---|
bin | 10111001010010010… |
… | …01101010110010111 |
3 | 1012002120101110111221 |
4 | 23211021031112113 |
5 | 200431142043111 |
6 | 5413502511211 |
7 | 620064032653 |
oct | 134511152627 |
9 | 35076343457 |
10 | 12434331031 |
11 | 5300945a41 |
12 | 24b0295507 |
13 | 1232136535 |
14 | 85d59ba63 |
15 | 4cb966371 |
hex | 2e524d597 |
12434331031 has 2 divisors, whose sum is σ = 12434331032. Its totient is φ = 12434331030.
The previous prime is 12434330999. The next prime is 12434331053. The reversal of 12434331031 is 13013343421.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 12434331031 - 25 = 12434330999 is a prime.
It is a super-2 number, since 2×124343310312 (a number of 21 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 12434330987 and 12434331005.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (12434331061) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6217165515 + 6217165516.
It is an arithmetic number, because the mean of its divisors is an integer number (6217165516).
Almost surely, 212434331031 is an apocalyptic number.
12434331031 is a deficient number, since it is larger than the sum of its proper divisors (1).
12434331031 is an equidigital number, since it uses as much as digits as its factorization.
12434331031 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 2592, while the sum is 25.
Adding to 12434331031 its reverse (13013343421), we get a palindrome (25447674452).
The spelling of 12434331031 in words is "twelve billion, four hundred thirty-four million, three hundred thirty-one thousand, thirty-one".
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