Base | Representation |
---|---|
bin | 111001111001101110… |
… | …0011101110101010011 |
3 | 102212221201001200220121 |
4 | 1303303130131311103 |
5 | 4014123403110003 |
6 | 133042250451111 |
7 | 11661226355221 |
oct | 1636334356523 |
9 | 385851050817 |
10 | 124343410003 |
11 | 4880868236a |
12 | 20122433a97 |
13 | b957cc5567 |
14 | 603812db11 |
15 | 337b461cbd |
hex | 1cf371dd53 |
124343410003 has 2 divisors, whose sum is σ = 124343410004. Its totient is φ = 124343410002.
The previous prime is 124343409973. The next prime is 124343410013. The reversal of 124343410003 is 300014343421.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 124343410003 - 217 = 124343278931 is a prime.
It is a super-2 number, since 2×1243434100032 (a number of 23 digits) contains 22 as substring.
It is a self number, because there is not a number n which added to its sum of digits gives 124343410003.
It is not a weakly prime, because it can be changed into another prime (124343410013) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 62171705001 + 62171705002.
It is an arithmetic number, because the mean of its divisors is an integer number (62171705002).
Almost surely, 2124343410003 is an apocalyptic number.
124343410003 is a deficient number, since it is larger than the sum of its proper divisors (1).
124343410003 is an equidigital number, since it uses as much as digits as its factorization.
124343410003 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 3456, while the sum is 25.
Adding to 124343410003 its reverse (300014343421), we get a palindrome (424357753424).
The spelling of 124343410003 in words is "one hundred twenty-four billion, three hundred forty-three million, four hundred ten thousand, three".
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