Base | Representation |
---|---|
bin | 10010000110000010011… |
… | …101000100001000000111 |
3 | 11101212112001211101001202 |
4 | 102012002131010020013 |
5 | 130333023124040303 |
6 | 2351120434213115 |
7 | 155556313234244 |
oct | 22060235041007 |
9 | 4355461741052 |
10 | 1243434205703 |
11 | 43a379213768 |
12 | 180b9b72419b |
13 | 90341cab441 |
14 | 4427ac485cb |
15 | 22527e34c88 |
hex | 12182744207 |
1243434205703 has 2 divisors, whose sum is σ = 1243434205704. Its totient is φ = 1243434205702.
The previous prime is 1243434205661. The next prime is 1243434205721. The reversal of 1243434205703 is 3075024343421.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 1243434205703 - 210 = 1243434204679 is a prime.
It is a super-2 number, since 2×12434342057032 (a number of 25 digits) contains 22 as substring.
It is a Sophie Germain prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1243434205303) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 621717102851 + 621717102852.
It is an arithmetic number, because the mean of its divisors is an integer number (621717102852).
Almost surely, 21243434205703 is an apocalyptic number.
1243434205703 is a deficient number, since it is larger than the sum of its proper divisors (1).
1243434205703 is an equidigital number, since it uses as much as digits as its factorization.
1243434205703 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 241920, while the sum is 38.
The spelling of 1243434205703 in words is "one trillion, two hundred forty-three billion, four hundred thirty-four million, two hundred five thousand, seven hundred three".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.072 sec. • engine limits •