Base | Representation |
---|---|
bin | 10010000110000010110… |
… | …100011011010110001010 |
3 | 11101212112111100112012002 |
4 | 102012002310123112022 |
5 | 130333031211030442 |
6 | 2351121213351002 |
7 | 155556416262554 |
oct | 22060264332612 |
9 | 4355474315162 |
10 | 1243440330122 |
11 | 43a381717071 |
12 | 180ba1798462 |
13 | 90343343c63 |
14 | 4427b9a04d4 |
15 | 22528744732 |
hex | 12182d1b58a |
1243440330122 has 4 divisors (see below), whose sum is σ = 1865160495186. Its totient is φ = 621720165060.
The previous prime is 1243440330101. The next prime is 1243440330137. The reversal of 1243440330122 is 2210330443421.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in only one way, i.e., 1242402266161 + 1038063961 = 1114631^2 + 32219^2 .
It is a super-2 number, since 2×12434403301222 (a number of 25 digits) contains 22 as substring.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 310860082529 + ... + 310860082532.
Almost surely, 21243440330122 is an apocalyptic number.
1243440330122 is a deficient number, since it is larger than the sum of its proper divisors (621720165064).
1243440330122 is an equidigital number, since it uses as much as digits as its factorization.
1243440330122 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 621720165063.
The product of its (nonzero) digits is 13824, while the sum is 29.
Adding to 1243440330122 its reverse (2210330443421), we get a palindrome (3453770773543).
The spelling of 1243440330122 in words is "one trillion, two hundred forty-three billion, four hundred forty million, three hundred thirty thousand, one hundred twenty-two".
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