Base | Representation |
---|---|
bin | 111001111011011100… |
… | …0001100110100110111 |
3 | 102220002201110012000202 |
4 | 1303312320030310313 |
5 | 4014233124341043 |
6 | 133052105231115 |
7 | 11662526104151 |
oct | 1636670146467 |
9 | 386081405022 |
10 | 124401012023 |
11 | 48838145642 |
12 | 2013979249b |
13 | b966c12bb2 |
14 | 6041a45ad1 |
15 | 338153e1b8 |
hex | 1cf6e0cd37 |
124401012023 has 2 divisors, whose sum is σ = 124401012024. Its totient is φ = 124401012022.
The previous prime is 124401012017. The next prime is 124401012037. The reversal of 124401012023 is 320210104421.
It is a weak prime.
It is an emirp because it is prime and its reverse (320210104421) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 124401012023 - 210 = 124401010999 is a prime.
It is a super-2 number, since 2×1244010120232 (a number of 23 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 124401011986 and 124401012004.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (124401012223) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 62200506011 + 62200506012.
It is an arithmetic number, because the mean of its divisors is an integer number (62200506012).
Almost surely, 2124401012023 is an apocalyptic number.
124401012023 is a deficient number, since it is larger than the sum of its proper divisors (1).
124401012023 is an equidigital number, since it uses as much as digits as its factorization.
124401012023 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 384, while the sum is 20.
Adding to 124401012023 its reverse (320210104421), we get a palindrome (444611116444).
The spelling of 124401012023 in words is "one hundred twenty-four billion, four hundred one million, twelve thousand, twenty-three".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.070 sec. • engine limits •