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12440134153 is a prime number
BaseRepresentation
bin10111001010111110…
…10110001000001001
31012002222022021220101
423211133112020021
5200434133243103
65414231125401
7620164252456
oct134537261011
935088267811
1012440134153
115304149a07
1224b2213861
1312333b8a35
1486026c82d
154cc210a1d
hex2e57d6209

12440134153 has 2 divisors, whose sum is σ = 12440134154. Its totient is φ = 12440134152.

The previous prime is 12440134127. The next prime is 12440134171. The reversal of 12440134153 is 35143104421.

12440134153 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 7446309264 + 4993824889 = 86292^2 + 70667^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-12440134153 is a prime.

It is not a weakly prime, because it can be changed into another prime (12440137153) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6220067076 + 6220067077.

It is an arithmetic number, because the mean of its divisors is an integer number (6220067077).

Almost surely, 212440134153 is an apocalyptic number.

It is an amenable number.

12440134153 is a deficient number, since it is larger than the sum of its proper divisors (1).

12440134153 is an equidigital number, since it uses as much as digits as its factorization.

12440134153 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 5760, while the sum is 28.

Adding to 12440134153 its reverse (35143104421), we get a palindrome (47583238574).

The spelling of 12440134153 in words is "twelve billion, four hundred forty million, one hundred thirty-four thousand, one hundred fifty-three".