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12440143433 is a prime number
BaseRepresentation
bin10111001010111110…
…11000011001001001
31012002222022202122002
423211133120121021
5200434134042213
65414231240345
7620164321514
oct134537303111
935088282562
1012440143433
115304155983
1224b22190b5
1312333c0023
14860271d7b
154cc213658
hex2e57d8649

12440143433 has 2 divisors, whose sum is σ = 12440143434. Its totient is φ = 12440143432.

The previous prime is 12440143421. The next prime is 12440143523. The reversal of 12440143433 is 33434104421.

It is a happy number.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 12197656249 + 242487184 = 110443^2 + 15572^2 .

It is an emirp because it is prime and its reverse (33434104421) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 12440143433 - 230 = 11366401609 is a prime.

It is a super-2 number, since 2×124401434332 (a number of 21 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 12440143396 and 12440143405.

It is not a weakly prime, because it can be changed into another prime (12440148433) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6220071716 + 6220071717.

It is an arithmetic number, because the mean of its divisors is an integer number (6220071717).

Almost surely, 212440143433 is an apocalyptic number.

It is an amenable number.

12440143433 is a deficient number, since it is larger than the sum of its proper divisors (1).

12440143433 is an equidigital number, since it uses as much as digits as its factorization.

12440143433 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 13824, while the sum is 29.

Adding to 12440143433 its reverse (33434104421), we get a palindrome (45874247854).

The spelling of 12440143433 in words is "twelve billion, four hundred forty million, one hundred forty-three thousand, four hundred thirty-three".