12440211233 has 4 divisors (see below), whose sum is σ = 12443013120. Its totient is φ = 12437409348.

The previous prime is 12440211197. The next prime is 12440211239. The reversal of 12440211233 is 33211204421.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 33211204421 = 8963 ⋅3705367.

It is a cyclic number.

It is not a de Polignac number, because 12440211233 - 2¹² = 12440207137 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 12440211199 and 12440211208.

It is not an unprimeable number, because it can be changed into a prime (12440211239) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1394273 + ... + 1403166.

It is an arithmetic number, because the mean of its divisors is an integer number (3110753280).

Almost surely, 2^12440211233 is an apocalyptic number.

It is an amenable number.

12440211233 is a deficient number, since it is larger than the sum of its proper divisors (2801887).

12440211233 is an equidigital number, since it uses as much as digits as its factorization.

12440211233 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 2801886.

The product of its (nonzero) digits is 1152, while the sum is 23.

Adding to 12440211233 its reverse (33211204421), we get a palindrome (45651415654).

The spelling of 12440211233 in words is "twelve billion, four hundred forty million, two hundred eleven thousand, two hundred thirty-three".