12440301137543 has 4 divisors (see below), whose sum is σ = 12442236775080. Its totient is φ = 12438365500008.

The previous prime is 12440301137533. The next prime is 12440301137557. The reversal of 12440301137543 is 34573110304421.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 12440301137543 - 2³⁴ = 12423121268359 is a prime.

It is a super-3 number, since 3×12440301137543³ (a number of 40 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 12440301137497 and 12440301137506.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (12440301137513) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 967809128 + ... + 967821981.

It is an arithmetic number, because the mean of its divisors is an integer number (3110559193770).

Almost surely, 2^{12440301137543} is an apocalyptic number.

12440301137543 is a deficient number, since it is larger than the sum of its proper divisors (1935637537).

12440301137543 is an equidigital number, since it uses as much as digits as its factorization.

12440301137543 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1935637536.

The product of its (nonzero) digits is 120960, while the sum is 38.

The spelling of 12440301137543 in words is "twelve trillion, four hundred forty billion, three hundred one million, one hundred thirty-seven thousand, five hundred forty-three".