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124403675413 is a prime number
BaseRepresentation
bin111001111011100001…
…0010111000100010101
3102220002220110111111211
41303313002113010111
54014234320103123
6133052242301421
711662560536143
oct1636702270425
9386086414454
10124403675413
11488396a4696
122013a657871
13b967636274
14604213a593
1533818b840d
hex1cf7097115

124403675413 has 2 divisors, whose sum is σ = 124403675414. Its totient is φ = 124403675412.

The previous prime is 124403675381. The next prime is 124403675441. The reversal of 124403675413 is 314576304421.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 67770146929 + 56633528484 = 260327^2 + 237978^2 .

It is a cyclic number.

It is not a de Polignac number, because 124403675413 - 25 = 124403675381 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (124403675443) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 62201837706 + 62201837707.

It is an arithmetic number, because the mean of its divisors is an integer number (62201837707).

Almost surely, 2124403675413 is an apocalyptic number.

It is an amenable number.

124403675413 is a deficient number, since it is larger than the sum of its proper divisors (1).

124403675413 is an equidigital number, since it uses as much as digits as its factorization.

124403675413 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 241920, while the sum is 40.

Adding to 124403675413 its reverse (314576304421), we get a palindrome (438979979834).

The spelling of 124403675413 in words is "one hundred twenty-four billion, four hundred three million, six hundred seventy-five thousand, four hundred thirteen".