Base | Representation |
---|---|
bin | 111001111011100001… |
… | …0010111000100010101 |
3 | 102220002220110111111211 |
4 | 1303313002113010111 |
5 | 4014234320103123 |
6 | 133052242301421 |
7 | 11662560536143 |
oct | 1636702270425 |
9 | 386086414454 |
10 | 124403675413 |
11 | 488396a4696 |
12 | 2013a657871 |
13 | b967636274 |
14 | 604213a593 |
15 | 33818b840d |
hex | 1cf7097115 |
124403675413 has 2 divisors, whose sum is σ = 124403675414. Its totient is φ = 124403675412.
The previous prime is 124403675381. The next prime is 124403675441. The reversal of 124403675413 is 314576304421.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 67770146929 + 56633528484 = 260327^2 + 237978^2 .
It is a cyclic number.
It is not a de Polignac number, because 124403675413 - 25 = 124403675381 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (124403675443) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 62201837706 + 62201837707.
It is an arithmetic number, because the mean of its divisors is an integer number (62201837707).
Almost surely, 2124403675413 is an apocalyptic number.
It is an amenable number.
124403675413 is a deficient number, since it is larger than the sum of its proper divisors (1).
124403675413 is an equidigital number, since it uses as much as digits as its factorization.
124403675413 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 241920, while the sum is 40.
Adding to 124403675413 its reverse (314576304421), we get a palindrome (438979979834).
The spelling of 124403675413 in words is "one hundred twenty-four billion, four hundred three million, six hundred seventy-five thousand, four hundred thirteen".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.072 sec. • engine limits •