Base | Representation |
---|---|
bin | 10111001011000110… |
… | …00011000010011001 |
3 | 1012010001010121000112 |
4 | 23211203003002121 |
5 | 200434410321122 |
6 | 5414304014105 |
7 | 620205433541 |
oct | 134543030231 |
9 | 35101117015 |
10 | 12441104537 |
11 | 5304751a84 |
12 | 24b2601335 |
13 | 1233668624 |
14 | 860442321 |
15 | 4cc3532e2 |
hex | 2e58c3099 |
12441104537 has 2 divisors, whose sum is σ = 12441104538. Its totient is φ = 12441104536.
The previous prime is 12441104521. The next prime is 12441104539. The reversal of 12441104537 is 73540114421.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 11670264841 + 770839696 = 108029^2 + 27764^2 .
It is an emirp because it is prime and its reverse (73540114421) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 12441104537 - 24 = 12441104521 is a prime.
Together with 12441104539, it forms a pair of twin primes.
It is a Chen prime.
It is not a weakly prime, because it can be changed into another prime (12441104539) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6220552268 + 6220552269.
It is an arithmetic number, because the mean of its divisors is an integer number (6220552269).
Almost surely, 212441104537 is an apocalyptic number.
It is an amenable number.
12441104537 is a deficient number, since it is larger than the sum of its proper divisors (1).
12441104537 is an equidigital number, since it uses as much as digits as its factorization.
12441104537 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 13440, while the sum is 32.
Adding to 12441104537 its reverse (73540114421), we get a palindrome (85981218958).
The spelling of 12441104537 in words is "twelve billion, four hundred forty-one million, one hundred four thousand, five hundred thirty-seven".
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