Base | Representation |
---|---|
bin | 10010000110101010111… |
… | …011111111010111111111 |
3 | 11101221021101212002022211 |
4 | 102012222323333113333 |
5 | 130340421012320333 |
6 | 2351312055521251 |
7 | 155612201266411 |
oct | 22065273772777 |
9 | 4357241762284 |
10 | 1244113401343 |
11 | 43a69764347a |
12 | 18114b089227 |
13 | 9041c915257 |
14 | 443031289b1 |
15 | 22567897ecd |
hex | 121aaeff5ff |
1244113401343 has 2 divisors, whose sum is σ = 1244113401344. Its totient is φ = 1244113401342.
The previous prime is 1244113401331. The next prime is 1244113401383. The reversal of 1244113401343 is 3431043114421.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 1244113401343 - 213 = 1244113393151 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1244113401383) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 622056700671 + 622056700672.
It is an arithmetic number, because the mean of its divisors is an integer number (622056700672).
Almost surely, 21244113401343 is an apocalyptic number.
1244113401343 is a deficient number, since it is larger than the sum of its proper divisors (1).
1244113401343 is an equidigital number, since it uses as much as digits as its factorization.
1244113401343 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 13824, while the sum is 31.
Adding to 1244113401343 its reverse (3431043114421), we get a palindrome (4675156515764).
The spelling of 1244113401343 in words is "one trillion, two hundred forty-four billion, one hundred thirteen million, four hundred one thousand, three hundred forty-three".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.078 sec. • engine limits •