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124411433 is a prime number
BaseRepresentation
bin1110110101001…
…01111000101001
322200002202101212
413122211320221
5223322131213
620202322505
73040323356
oct732457051
9280082355
10124411433
1164255173
12357b9435
131ca0cb43
141274762d
15adc79a8
hex76a5e29

124411433 has 2 divisors, whose sum is σ = 124411434. Its totient is φ = 124411432.

The previous prime is 124411403. The next prime is 124411451. The reversal of 124411433 is 334114421.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 95981209 + 28430224 = 9797^2 + 5332^2 .

It is a cyclic number.

It is not a de Polignac number, because 124411433 - 212 = 124407337 is a prime.

It is a super-2 number, since 2×1244114332 = 30956409322226978, which contains 22 as substring.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 124411399 and 124411408.

It is not a weakly prime, because it can be changed into another prime (124411403) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 62205716 + 62205717.

It is an arithmetic number, because the mean of its divisors is an integer number (62205717).

Almost surely, 2124411433 is an apocalyptic number.

It is an amenable number.

124411433 is a deficient number, since it is larger than the sum of its proper divisors (1).

124411433 is an equidigital number, since it uses as much as digits as its factorization.

124411433 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 1152, while the sum is 23.

The square root of 124411433 is about 11153.9873139609. The cubic root of 124411433 is about 499.2140090840.

Adding to 124411433 its reverse (334114421), we get a palindrome (458525854).

The spelling of 124411433 in words is "one hundred twenty-four million, four hundred eleven thousand, four hundred thirty-three".