12441164963 has 2 divisors, whose sum is σ = 12441164964. Its totient is φ = 12441164962.

The previous prime is 12441164929. The next prime is 12441164999. The reversal of 12441164963 is 36946114421.

12441164963 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-12441164963 is a prime.

It is a super-3 number, since 3×12441164963³ (a number of 31 digits) contains 333 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 12441164963.

It is not a weakly prime, because it can be changed into another prime (12441163963) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6220582481 + 6220582482.

It is an arithmetic number, because the mean of its divisors is an integer number (6220582482).

Almost surely, 2^12441164963 is an apocalyptic number.

12441164963 is a deficient number, since it is larger than the sum of its proper divisors (1).

12441164963 is an equidigital number, since it uses as much as digits as its factorization.

12441164963 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 124416, while the sum is 41.

The spelling of 12441164963 in words is "twelve billion, four hundred forty-one million, one hundred sixty-four thousand, nine hundred sixty-three".