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1244131143133 is a prime number
BaseRepresentation
bin10010000110101011111…
…111101010110111011101
311101221022122020110111011
4102012223333222313131
5130340440033040013
62351313532055221
7155612505141634
oct22065377526735
94357278213434
101244131143133
1143a6a666110a
12181155004511
13904234b7858
144430562651b
15225691eec3d
hex121abfeaddd

1244131143133 has 2 divisors, whose sum is σ = 1244131143134. Its totient is φ = 1244131143132.

The previous prime is 1244131143121. The next prime is 1244131143149. The reversal of 1244131143133 is 3313411314421.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 1238619862489 + 5511280644 = 1112933^2 + 74238^2 .

It is a cyclic number.

It is not a de Polignac number, because 1244131143133 - 233 = 1235541208541 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 1244131143095 and 1244131143104.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1244131143103) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 622065571566 + 622065571567.

It is an arithmetic number, because the mean of its divisors is an integer number (622065571567).

Almost surely, 21244131143133 is an apocalyptic number.

It is an amenable number.

1244131143133 is a deficient number, since it is larger than the sum of its proper divisors (1).

1244131143133 is an equidigital number, since it uses as much as digits as its factorization.

1244131143133 is an evil number, because the sum of its binary digits is even.

The product of its digits is 10368, while the sum is 31.

Adding to 1244131143133 its reverse (3313411314421), we get a palindrome (4557542457554).

The spelling of 1244131143133 in words is "one trillion, two hundred forty-four billion, one hundred thirty-one million, one hundred forty-three thousand, one hundred thirty-three".