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1244213130451 is a prime number
BaseRepresentation
bin10010000110110000111…
…000011011010011010011
311101221112100111211221111
4102012300320123103103
5130341122030133301
62351330021234151
7155614522053004
oct22066070332323
94357470454844
101244213130451
1143a73896a425
12181178562957
1390437492665
14443124891ab
15225714e7551
hex121b0e1b4d3

1244213130451 has 2 divisors, whose sum is σ = 1244213130452. Its totient is φ = 1244213130450.

The previous prime is 1244213130443. The next prime is 1244213130469. The reversal of 1244213130451 is 1540313124421.

It is a happy number.

It is a weak prime.

It is an emirp because it is prime and its reverse (1540313124421) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 1244213130451 - 23 = 1244213130443 is a prime.

It is not a weakly prime, because it can be changed into another prime (1244213130491) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 622106565225 + 622106565226.

It is an arithmetic number, because the mean of its divisors is an integer number (622106565226).

Almost surely, 21244213130451 is an apocalyptic number.

1244213130451 is a deficient number, since it is larger than the sum of its proper divisors (1).

1244213130451 is an equidigital number, since it uses as much as digits as its factorization.

1244213130451 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 11520, while the sum is 31.

Adding to 1244213130451 its reverse (1540313124421), we get a palindrome (2784526254872).

The spelling of 1244213130451 in words is "one trillion, two hundred forty-four billion, two hundred thirteen million, one hundred thirty thousand, four hundred fifty-one".