Base | Representation |
---|---|
bin | 111001111100000100… |
… | …0010100000111011010 |
3 | 102220011011222011111121 |
4 | 1303320020110013122 |
5 | 4014304013412102 |
6 | 133054135315454 |
7 | 11663202443521 |
oct | 1637010240732 |
9 | 386134864447 |
10 | 124422013402 |
11 | 48848a8a255 |
12 | 2014481bb8a |
13 | b96b38704b |
14 | 60447514b8 |
15 | 33832dbb37 |
hex | 1cf82141da |
124422013402 has 4 divisors (see below), whose sum is σ = 186633020106. Its totient is φ = 62211006700.
The previous prime is 124422013351. The next prime is 124422013421. The reversal of 124422013402 is 204310224421.
It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 204310224421 = 74941 ⋅2726281.
It can be written as a sum of positive squares in only one way, i.e., 74299311241 + 50122702161 = 272579^2 + 223881^2 .
It is a super-2 number, since 2×1244220134022 (a number of 23 digits) contains 22 as substring.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 31105503349 + ... + 31105503352.
Almost surely, 2124422013402 is an apocalyptic number.
124422013402 is a deficient number, since it is larger than the sum of its proper divisors (62211006704).
124422013402 is an equidigital number, since it uses as much as digits as its factorization.
124422013402 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 62211006703.
The product of its (nonzero) digits is 3072, while the sum is 25.
Adding to 124422013402 its reverse (204310224421), we get a palindrome (328732237823).
The spelling of 124422013402 in words is "one hundred twenty-four billion, four hundred twenty-two million, thirteen thousand, four hundred two".
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