12443301041 has 4 divisors (see below), whose sum is σ = 12444782592. Its totient is φ = 12441819492.

The previous prime is 12443300993. The next prime is 12443301053. The reversal of 12443301041 is 14010334421.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 12443301041 - 2¹⁰ = 12443300017 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 12443300998 and 12443301016.

It is not an unprimeable number, because it can be changed into a prime (12443309041) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 728105 + ... + 744998.

It is an arithmetic number, because the mean of its divisors is an integer number (3111195648).

Almost surely, 2^12443301041 is an apocalyptic number.

It is an amenable number.

12443301041 is a deficient number, since it is larger than the sum of its proper divisors (1481551).

12443301041 is an equidigital number, since it uses as much as digits as its factorization.

12443301041 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1481550.

The product of its (nonzero) digits is 1152, while the sum is 23.

Adding to 12443301041 its reverse (14010334421), we get a palindrome (26453635462).

The spelling of 12443301041 in words is "twelve billion, four hundred forty-three million, three hundred one thousand, forty-one".