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12443333310050 = 252547454966483
BaseRepresentation
bin1011010100010011000001…
…1101100011011001100010
31122001120102021220201001112
42311010300131203121202
53112332421311410200
642244215521303322
72423000253662306
oct265046035433142
948046367821045
1012443333310050
113a68208290435
12148b727194b42
136c352a856296
14310390d19d06
15168a2dc83535
hexb5130763662

12443333310050 has 24 divisors (see below), whose sum is σ = 23186911890576. Its totient is φ = 4968233983440.

The previous prime is 12443333310019. The next prime is 12443333310073. The reversal of 12443333310050 is 5001333334421.

It is a junction number, because it is equal to n+sod(n) for n = 12443333309989 and 12443333310016.

It is an unprimeable number.

It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 227455892 + ... + 227510591.

It is an arithmetic number, because the mean of its divisors is an integer number (966121328774).

Almost surely, 212443333310050 is an apocalyptic number.

12443333310050 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

12443333310050 is a deficient number, since it is larger than the sum of its proper divisors (10743578580526).

12443333310050 is a wasteful number, since it uses less digits than its factorization.

12443333310050 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 454967042 (or 454967037 counting only the distinct ones).

The product of its (nonzero) digits is 38880, while the sum is 32.

Adding to 12443333310050 its reverse (5001333334421), we get a palindrome (17444666644471).

The spelling of 12443333310050 in words is "twelve trillion, four hundred forty-three billion, three hundred thirty-three million, three hundred ten thousand, fifty".

Divisors: 1 2 5 10 25 50 547 1094 2735 5470 13675 27350 454966483 909932966 2274832415 4549664830 11374162075 22748324150 248866666201 497733332402 1244333331005 2488666662010 6221666655025 12443333310050