12444143113 has 2 divisors, whose sum is σ = 12444143114. Its totient is φ = 12444143112.

The previous prime is 12444143053. The next prime is 12444143171. The reversal of 12444143113 is 31134144421.

12444143113 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 12256261264 + 187881849 = 110708^2 + 13707^2 .

It is an emirp because it is prime and its reverse (31134144421) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-12444143113 is a prime.

It is not a weakly prime, because it can be changed into another prime (12444143213) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6222071556 + 6222071557.

It is an arithmetic number, because the mean of its divisors is an integer number (6222071557).

Almost surely, 2^12444143113 is an apocalyptic number.

It is an amenable number.

12444143113 is a deficient number, since it is larger than the sum of its proper divisors (1).

12444143113 is an equidigital number, since it uses as much as digits as its factorization.

12444143113 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 4608, while the sum is 28.

Adding to 12444143113 its reverse (31134144421), we get a palindrome (43578287534).

The spelling of 12444143113 in words is "twelve billion, four hundred forty-four million, one hundred forty-three thousand, one hundred thirteen".