Base | Representation |
---|---|
bin | 10111001100001101… |
… | …11001110100101111 |
3 | 1012010200211010122011 |
4 | 23212012321310233 |
5 | 200444312111413 |
6 | 5415241302051 |
7 | 620351352301 |
oct | 134606716457 |
9 | 35120733564 |
10 | 12450503983 |
11 | 5309a91a15 |
12 | 24b5794927 |
13 | 12355a9a28 |
14 | 8617ab971 |
15 | 4cd0ad33d |
hex | 2e61b9d2f |
12450503983 has 2 divisors, whose sum is σ = 12450503984. Its totient is φ = 12450503982.
The previous prime is 12450503971. The next prime is 12450504089. The reversal of 12450503983 is 38930505421.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 12450503983 - 25 = 12450503951 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (12450503903) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6225251991 + 6225251992.
It is an arithmetic number, because the mean of its divisors is an integer number (6225251992).
Almost surely, 212450503983 is an apocalyptic number.
12450503983 is a deficient number, since it is larger than the sum of its proper divisors (1).
12450503983 is an equidigital number, since it uses as much as digits as its factorization.
12450503983 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 129600, while the sum is 40.
The spelling of 12450503983 in words is "twelve billion, four hundred fifty million, five hundred three thousand, nine hundred eighty-three".
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