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124553132112551 is a prime number
BaseRepresentation
bin11100010100011111001001…
…001100011111101010100111
3121100000011101221010102102112
4130110133021030133222213
5112311134303310100201
61120522530255431235
735143444503445112
oct3424371114375247
9540004357112375
10124553132112551
1136760760a9089a
1211b77293b2551b
135466404ca260c
1422a8591cb9579
15e5eda5a770bb
hex7147c931faa7

124553132112551 has 2 divisors, whose sum is σ = 124553132112552. Its totient is φ = 124553132112550.

The previous prime is 124553132112473. The next prime is 124553132112667. The reversal of 124553132112551 is 155211231355421.

It is a weak prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-124553132112551 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 124553132112499 and 124553132112508.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (124553132102551) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 62276566056275 + 62276566056276.

It is an arithmetic number, because the mean of its divisors is an integer number (62276566056276).

Almost surely, 2124553132112551 is an apocalyptic number.

124553132112551 is a deficient number, since it is larger than the sum of its proper divisors (1).

124553132112551 is an equidigital number, since it uses as much as digits as its factorization.

124553132112551 is an evil number, because the sum of its binary digits is even.

The product of its digits is 180000, while the sum is 41.

Adding to 124553132112551 its reverse (155211231355421), we get a palindrome (279764363467972).

The spelling of 124553132112551 in words is "one hundred twenty-four trillion, five hundred fifty-three billion, one hundred thirty-two million, one hundred twelve thousand, five hundred fifty-one".