Base | Representation |
---|---|
bin | 11100010100011111001001… |
… | …001100011111101010100111 |
3 | 121100000011101221010102102112 |
4 | 130110133021030133222213 |
5 | 112311134303310100201 |
6 | 1120522530255431235 |
7 | 35143444503445112 |
oct | 3424371114375247 |
9 | 540004357112375 |
10 | 124553132112551 |
11 | 36760760a9089a |
12 | 11b77293b2551b |
13 | 5466404ca260c |
14 | 22a8591cb9579 |
15 | e5eda5a770bb |
hex | 7147c931faa7 |
124553132112551 has 2 divisors, whose sum is σ = 124553132112552. Its totient is φ = 124553132112550.
The previous prime is 124553132112473. The next prime is 124553132112667. The reversal of 124553132112551 is 155211231355421.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-124553132112551 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 124553132112499 and 124553132112508.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (124553132102551) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 62276566056275 + 62276566056276.
It is an arithmetic number, because the mean of its divisors is an integer number (62276566056276).
Almost surely, 2124553132112551 is an apocalyptic number.
124553132112551 is a deficient number, since it is larger than the sum of its proper divisors (1).
124553132112551 is an equidigital number, since it uses as much as digits as its factorization.
124553132112551 is an evil number, because the sum of its binary digits is even.
The product of its digits is 180000, while the sum is 41.
Adding to 124553132112551 its reverse (155211231355421), we get a palindrome (279764363467972).
The spelling of 124553132112551 in words is "one hundred twenty-four trillion, five hundred fifty-three billion, one hundred thirty-two million, one hundred twelve thousand, five hundred fifty-one".
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