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12471235365353 is a prime number
BaseRepresentation
bin1011010101111010111110…
…0011011100100111101001
31122011020102211112222100012
42311132233203130213221
53113312042223142403
642305112331221305
72425005560354312
oct265365743344751
948136384488305
1012471235365353
113a7902626a576
1214950135a7835
136c605639cb8b
1431187a891609
151696135eded8
hexb57af8dc9e9

12471235365353 has 2 divisors, whose sum is σ = 12471235365354. Its totient is φ = 12471235365352.

The previous prime is 12471235365313. The next prime is 12471235365367. The reversal of 12471235365353 is 35356353217421.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 12190174222249 + 281061143104 = 3491443^2 + 530152^2 .

It is an emirp because it is prime and its reverse (35356353217421) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 12471235365353 - 28 = 12471235365097 is a prime.

It is not a weakly prime, because it can be changed into another prime (12471235365313) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6235617682676 + 6235617682677.

It is an arithmetic number, because the mean of its divisors is an integer number (6235617682677).

Almost surely, 212471235365353 is an apocalyptic number.

It is an amenable number.

12471235365353 is a deficient number, since it is larger than the sum of its proper divisors (1).

12471235365353 is an equidigital number, since it uses as much as digits as its factorization.

12471235365353 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 6804000, while the sum is 50.

The spelling of 12471235365353 in words is "twelve trillion, four hundred seventy-one billion, two hundred thirty-five million, three hundred sixty-five thousand, three hundred fifty-three".