Base | Representation |
---|---|
bin | 10111001110101100… |
… | …00000101100111101 |
3 | 1012012010211201012120 |
4 | 23213112000230331 |
5 | 201020114212113 |
6 | 5421301553153 |
7 | 621022542522 |
oct | 134726005475 |
9 | 35163751176 |
10 | 12471241533 |
11 | 531a766393 |
12 | 25007157b9 |
13 | 123998aa7a |
14 | 864449149 |
15 | 4ced07a23 |
hex | 2e7580b3d |
12471241533 has 4 divisors (see below), whose sum is σ = 16628322048. Its totient is φ = 8314161020.
The previous prime is 12471241481. The next prime is 12471241537. The reversal of 12471241533 is 33514217421.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 12471241533 - 229 = 11934370621 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 12471241494 and 12471241503.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (12471241537) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2078540253 + ... + 2078540258.
It is an arithmetic number, because the mean of its divisors is an integer number (4157080512).
Almost surely, 212471241533 is an apocalyptic number.
It is an amenable number.
12471241533 is a deficient number, since it is larger than the sum of its proper divisors (4157080515).
12471241533 is an equidigital number, since it uses as much as digits as its factorization.
12471241533 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 4157080514.
The product of its digits is 20160, while the sum is 33.
Adding to 12471241533 its reverse (33514217421), we get a palindrome (45985458954).
The spelling of 12471241533 in words is "twelve billion, four hundred seventy-one million, two hundred forty-one thousand, five hundred thirty-three".
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