12481432035 has 32 divisors (see below), whose sum is σ = 20252989440. Its totient is φ = 6563088000.

The previous prime is 12481432027. The next prime is 12481432043. The reversal of 12481432035 is 53023418421.

It is an interprime number because it is at equal distance from previous prime (12481432027) and next prime (12481432043).

It is not a de Polignac number, because 12481432035 - 2³ = 12481432027 is a prime.

It is a super-3 number, since 3×12481432035³ (a number of 31 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a junction number, because it is equal to n+sod(n) for n = 12481431987 and 12481432005.

It is an unprimeable number.

It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 344850 + ... + 379320.

It is an arithmetic number, because the mean of its divisors is an integer number (632905920).

Almost surely, 2^12481432035 is an apocalyptic number.

12481432035 is a gapful number since it is divisible by the number (15) formed by its first and last digit.

12481432035 is a deficient number, since it is larger than the sum of its proper divisors (7771557405).

12481432035 is a wasteful number, since it uses less digits than its factorization.

12481432035 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 34819.

The product of its (nonzero) digits is 23040, while the sum is 33.

The spelling of 12481432035 in words is "twelve billion, four hundred eighty-one million, four hundred thirty-two thousand, thirty-five".