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1248241613953 is a prime number
BaseRepresentation
bin10010001010100000111…
…111110111110010000001
311102022221002211000102011
4102022200333313302001
5130422344323121303
62353233445452521
7156116406440605
oct22124077676201
94368832730364
101248241613953
11441415938734
12181b01711141
1390929c779c9
14445b54d5505
1522709ee716d
hex122a0ff7c81

1248241613953 has 2 divisors, whose sum is σ = 1248241613954. Its totient is φ = 1248241613952.

The previous prime is 1248241613951. The next prime is 1248241614047. The reversal of 1248241613953 is 3593161428421.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 1090963538064 + 157278075889 = 1044492^2 + 396583^2 .

It is an emirp because it is prime and its reverse (3593161428421) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 1248241613953 - 21 = 1248241613951 is a prime.

Together with 1248241613951, it forms a pair of twin primes.

It is a junction number, because it is equal to n+sod(n) for n = 1248241613897 and 1248241613906.

It is not a weakly prime, because it can be changed into another prime (1248241613951) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 624120806976 + 624120806977.

It is an arithmetic number, because the mean of its divisors is an integer number (624120806977).

Almost surely, 21248241613953 is an apocalyptic number.

It is an amenable number.

1248241613953 is a deficient number, since it is larger than the sum of its proper divisors (1).

1248241613953 is an equidigital number, since it uses as much as digits as its factorization.

1248241613953 is an evil number, because the sum of its binary digits is even.

The product of its digits is 1244160, while the sum is 49.

The spelling of 1248241613953 in words is "one trillion, two hundred forty-eight billion, two hundred forty-one million, six hundred thirteen thousand, nine hundred fifty-three".